How do you differentiate $g(t)= 7/sqrt(t)$ ?

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Answer 1 · 2016-11-15T02:59:05

$g'(t)=(-7)/(2t^(3/2))$

$g(t)=7/(sqrtt)$

This can be solved multiple ways, such as using the quotient rule, or using the power rule. I prefer the power rule so I will rewrite $g(t)$ :

$g(t)=7/(t^(1/2))$
$g(t)=7t^(-1/2)$

Now to differentiate $g(t)$ , use the power rule:

$g'(t)=(-1/2)(7)(t^(-3/2))$
$g'(t)=(-7/2)(t^(-3/2))$

$g'(t)=(-7)/(2t^(3/2))$

How do you differentiate g(t)= 7/sqrt(t)g(t)= 7/sqrt(t)?