How do you differentiate $s=(1+sint)/(1+tant)$ ?

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Answer 1 · 2017-12-18T08:55:19

$s'=(cost(1+tant)-sec^2t(1+sint))/(1+tant)^2$

$s=(1+sint)/(1+tant)=u/v$

$s'=(vu'-uv')/v^2$

$u=1+sint$
$u'=cost$

$v=1+tant$
$v'=sec^2t$

$s'=(cost(1+tant)-sec^2t(1+sint))/(1+tant)^2$

How do you differentiate s=(1+sint)/(1+tant)s=(1+sint)/(1+tant)?