How do you differentiate $\frac{x + 1}{x - 1}$ $(x+1)/(x-1)$ ?

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Answer 1 · 2018-06-09T15:24:12

$- \frac{2}{{(x - 1)}^{2}}$ $-2/(x-1)^2$

$(u/v)'=(u'v-uv')/v^2$
we get

$f'(x)=(x-1-(x+1))/(x-1)^2=-2/(x-1)^2$

How do you differentiate (x+1)/(x-1)x+1x−1(x+1)/(x-1)?