How do you differentiate $(x-3)/(2x+1)$ ?

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Answer 1 · 2015-05-14T12:24:52

Quocient rule time!

By quocient rule's definition, we have:

$(dy)/(dx) = (f(x))/(g(x)) = (f'(x)*g(x) - f(x)*g'(x))/((f(x))^2)$

Now, let's just proceed:

$(dy)/(dx) = (1*(2x+1) - (x-3)*2)/(x-3)^2$ $= (7)/(x^2-6x+9)$

:)

How do you differentiate (x-3)/(2x+1)(x-3)/(2x+1)?