How do you differentiate $x / (x^2 + 1)^(1/2)$ ?

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Answer 1 · 2018-05-13T21:47:14

$d/dx ( x/(x^2+1)^(1/2)) =1/(x^2+1)^(3/2)$

$d/dx ( x/(x^2+1)^(1/2)) = ( (x^2+1)^(1/2) - x (2x)/(2(x^2+1)^(1/2)))/(x^2+1)$

$d/dx ( x/(x^2+1)^(1/2)) = (x^2 +1 -x^2)/(x^2+1)^(3/2)$

$d/dx ( x/(x^2+1)^(1/2)) =1/(x^2+1)^(3/2)$

How do you differentiate x / (x^2 + 1)^(1/2)x / (x^2 + 1)^(1/2)?