How do you differentiate $y = x / (x^2 + 3 )$ ?

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Answer 1 · 2016-01-17T08:43:15

$dy/dx=(3-x^2)/(x^2 +3)^2$

Use the formula for derivatives of quotients

$d/dx(u/v)=(v (du)/dx-u (dv)/dx)/v^2$

Let $u=x$
Let $v=x^2+3$

$dy/dx=((x^2+3)*1-x(2x))/(x^2+3)^2$

$dy/dx=(3-x^2)/(x^2 +3)^2$

How do you differentiate y = x / (x^2 + 3 )y = x / (x^2 + 3 )?