How do you find antiderivative of $2 \cdot \sqrt{sin x}$ $2*sqrt(sin x)$ ?

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How do you find antiderivative of $2 \cdot \sqrt{sin x}$ $2*sqrt(sin x)$ ?

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Answer 1 · 2015-04-13T15:41:23

I'm fairly confident that the antiderivative is not a function expressible using algebraic combinations of algebraic/trigonometric and logarithmic/exponential functions.

We can write it as $f (x) = C + \int \sqrt{sin x} d x$ $f(x) =C+ int sqrt(sinx) dx$ for constant $C$ $C$ . But, other than giving that a name, we're done.

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How do you find antiderivative of $2 \cdot \sqrt{sin x}$ $2*sqrt(sin x)$ ?

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How do you find antiderivative of $2 \cdot \sqrt{sin x}$ $2*sqrt(sin x)$ ?