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How do you find the antiderivative $4 + 4 {tan}^{2} x$ $4 + 4tan^2x$ ?

1 Answer

Apr 14, 2015

4tan x +C

4+4 ${tan}^{2}$ $tan^2$ x would be 4 (1 + ${tan}^{2}$ $tan^2$ x) or 4 ${sec}^{2}$ $sec^2$ x

Antiderivative of ${sec}^{2}$ $sec^2$ x is tanx. Hence the required answer would be 4tanx+C

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