How do you find the antiderivative of (2e^(.2x)-cosx)?
1 Answer
Apr 12, 2017
Explanation:
int(2e^(0.2x)-cosx)dx
=1/(0.2)xx2e^(0.2x)-sinx
=10e^(0.2x)-sinx
int(2e^(0.2x)-cosx)dx
=1/(0.2)xx2e^(0.2x)-sinx
=10e^(0.2x)-sinx