How do you find the antiderivative of $cos(2x)$ ?

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Answer 1 · 2016-11-22T14:53:42

$=1/2sin(2x)+C$

$intcos(2x)dx$

Let $u=2x$
$(du)/(dx)=2$
$(du)/2=dx$

Substitute in u:
$intcos(u)(du)/2$
$=1/2intcos(u)du$
$=1/2sinu+C$

Re-substitute the value of u:
$=1/2sin(2x)+C$

How do you find the antiderivative of cos(2x)cos(2x)?