How do you find the antiderivative of $cos^3 (x)dx$ ?

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Answer 1 · 2016-06-23T08:41:48

$sin x- 1/3 sin^3x + C$

$\int cos^3 x \ dx = = \int cosx(cos^2x) \ dx= \int cosx(1-sin^2x) \ dx$ and that's pretty much it

because

$\int cosx(1-sin^2x) \ dx$

$= \int cosx- cosx sin^2x \ dx$

$= sin x- 1/3 sin^3x + C$

How do you find the antiderivative of cos^3 (x)dxcos^3 (x)dx?