How do you find the antiderivative of ${cos}^{4} x sin (2 x) d x$ $cos^4 x sin(2x) dx$ ?

Question

1577 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-20T11:25:19

$= - \frac{1}{3} {cos}^{6} x + C$ $= -1/3 cos^6x + C$

use $sin 2 A = 2 sin A cos A$ $sin 2A = 2 sin A cos A$

it becomes $2 int \ cos^5x sin x \ dx$

$= 2 int -1/6\d/dx( cos^6 x) \ dx$

$= -1/3 cos^6x + C$

How do you find the antiderivative of cos^4 x sin(2x) dxcos4xsin(2x)dxcos^4 x sin(2x) dx?