How do you find the antiderivative of $(cosx)^2$ ?

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Answer 1 · 2016-07-27T08:08:05

$intcos^2xdx=x/2+(sin2x)/4+c$

To find antiderivative i.e. integral of $cos^2x$ , we can use formula $cos^2x=1/2(1+cos2x)$

$intcos^2xdx=int[1/2(1+cos2x)]dx$

= $int(1/2+(cos2x)/2)dx$

= $1/2[x+(sin2x)/2]+c$

= $x/2+(sin2x)/4+c$

How do you find the antiderivative of (cosx)^2(cosx)^2?