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How do you find the antiderivative of $sin(x)cos(x)$ ?

1 Answer

Aug 11, 2016

$-1/4cos2x+C$ .

Explanation:

$I-intsinxcosxdx=1/2int2sinxcosxdx=1/2intsin2xdx$

$=1/2(cos(2x)/2)=-1/4cos2x+C$ .

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