Question

How do you find the antiderivative of `sin(x)cos(x)`?

Answer 1

`-1/4cos2x+C`.

Explanation:

`I-intsinxcosxdx=1/2int2sinxcosxdx=1/2intsin2xdx`

`=1/2(cos(2x)/2)=-1/4cos2x+C`.