How do you find the antiderivative of $sin x$ $sinx$ ?

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Answer 1 · 2018-04-10T12:19:26

$\int sin x d x = - cos x + c$ $intsinxdx=-cosx+"c"$

The antiderivative of sinx is its integral. The integral of $sin x$ $sinx$ is a standard results and evaluates to

$\int sin x d x = - cos x + c$ $intsinxdx=-cosx+"c"$

Answer 2 · 2018-04-10T12:53:05

$- cos (x) + C$ $-cos(x)+C$

The anti-derivative of a function $f (x)$ $f(x)$ is the same thing as the integral of the function, i.e. it's $intf(x) \ dx$ .

So, the anti-derivative of $sin(x)$ will be:

$intsin(x) \ dx$

This is a common integral, and it equals,

$=-cos(x)+C$

How do you find the antiderivative of sinxsinxsinx?