How do you find the area of triangle ABC given A=10, B=48, C=122, c=11?

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Answer 1 · 2018-02-25T17:20:44

So,the picture looks like this,

enter image source here

So, #a/sin A = b/ sin B = c/ sin C#

So, #a = c (sin A/sin B)=2.56#

and, #b = c(sin B/sin C)=9.64#

So, #s=(11+2.56+9.64)/2=11.6#

So, area of the triangle is = #sqrt(s(s-a)(s-b)(s-c))=11.105# #unit^2#