Question

How do you find the derivative of `8/x^2`?

Answer 1

One law of exponentials states that `a^-n=1/a^n`

Thus, we can rewrite this again as `8x^-2`

Now, derivating the function:

`(dy)/(dx)=8(-2)x^-3=-16x^-3`

If you prefer, `-16/x^3`