How do you find the derivative of $y=1/x^2$ ?

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Answer 1 · 2016-01-14T15:41:47

$dy /dx = -2/x^3$

The derivative of $y = ax^n$

is $dy/dx = nax^(n-1)$

By rewriting $y = 1/x^2$ as $y = x^(-2)$

then it is in the form $ax^n$

$rArrdy/dx = - 2x^(-3) = - 2/(x^3)$

How do you find the derivative of y=1/x^2y=1/x^2?