How do you find the integral of $1/(sin^2(x))$ ?

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Answer 1 · 2016-07-03T03:36:22

                  #=-2*csc^2(x)*cot(x)#

$1/sin^2(x) = csc^2(x)$

Treat $csc^2(x)$ as $(csc(x))^2$ .

Using power rule, bring down 2 as coefficient.

That would give us $2*csc(x)$

Don't forget chain rule and multiply with the derivative of $csc(x)$ .

We know that the derivative of $csc(x)$ is $-cot(x)*csc(x)$ .

$d/dx csc^2(x)=-2*csc(x)*cot(x)*csc(x)$
$=-2*csc^2(x)*cot(x)$

How do you find the integral of 1/(sin^2(x))1/(sin^2(x))?