How do you find the integral of $int (sin x)/(cos^3 x) dx$ ?

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Answer 1 · 2015-10-07T12:55:43

The numerator is almost the derivative of $cosx$ , try a substitution.

The denominator is seen to be (cosx)^3., the numerator is $-d/dx(cosx)$ this suggestets that we try the substitution $u=cosx$ .

How do you find the integral of int (sin x)/(cos^3 x) dxint (sin x)/(cos^3 x) dx?