Question

How do you find the integral of `sec(3x)sec(3x)`?

Answer 1

`1/3\tan(3x)+C`

Explanation:

Given that

`\int \sec(3x)\sec(3x)\ dx`

`=\int \sec^2(3x)\ dx`

`=1/3\int \sec^2(3x)\3 dx`

`=1/3\int \sec^2(3x)\d(3x)`

`=1/3\tan(3x)+C`