How do you find the limit of $xlnx$ as $x->oo$ ?

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Answer 1 · 2017-11-18T07:16:39

The answer is $=oo$

In this exercise $x>0$

$lim_(x->oo)x=oo$

$lim_(x->oo)lnx=oo$

Therefore,

$lim_(x->oo)xlnx=oo*oo=oo$

A big number times a big number is a big number.

graph{xlnx [-10, 10, -5, 5]}

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