Question

How do you graph `y=sqrt(x-2)+3`?

Answer 1

See the explanation

Explanation:

Suppose there was an unknown value z

Then `(-z)^2 =z^2" and "(+z)^2=z^2`

So `sqrt(z^2)=+-z`
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So in reality we have `y=+-sqrt(x-2)+3`

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Lets consider the relationship a different way. The above is such that `x` is the independent variable and y the dependant variable. Suppose we reversed this.

Write as `sqrt(x-2)=y-3`

Squaring both sides

`x-2=y^2-6y+9`

`x=y^2-6y+11`

If you plotted this then you would have the same graph as
`y=+-sqrt(x-2)+3`