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How do you integrate $\frac{1 - tan 2 x}{sec 2 x} d x$ $(1-tan2x)/(sec2x)dx$ ?

1 Answer

Feb 19, 2015

You get: $\frac{sin (2 x)}{2} + \frac{cos (2 x)}{2} + c$ $sin(2x)/2+cos(2x)/2+c$

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