How do you integrate ${(csc 2 x - cot 2 x)}^{2} d x$ $(csc2x-cot2x)^2 dx$ ?

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How do you integrate ${(csc 2 x - cot 2 x)}^{2} d x$ $(csc2x-cot2x)^2 dx$ ?

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Answer 1 · 2015-02-26T12:25:03

I would start by writing it changing:
$csc (2 x) = \frac{1}{sin (2 x)}$ $csc(2x)=1/(sin(2x))$
$cot (2 x) = \frac{cos (2 x)}{sin (2 x)}$ $cot(2x)=(cos(2x))/(sin(2x))$
And:
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How do you integrate ${(csc 2 x - cot 2 x)}^{2} d x$ $(csc2x-cot2x)^2 dx$ ?

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How do you integrate (csc2x-cot2x)^2 dx(csc2x−cot2x)2dx(csc2x-cot2x)^2 dx?

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How do you integrate ${(csc 2 x - cot 2 x)}^{2} d x$ $(csc2x-cot2x)^2 dx$ ?