Question

How do you integrate `f(t) = 5cos(10t) + 12e^-3t`?

Answer 1

I am not sure about the last bit with `e`;
If it is like you wrote you should get:
`int(5cos(10t)+12e^-3t)dt=5sin(10t)/10+12e^-3t^2/2+c=sin(10t)/2+6e^-3t^2+c`
Where `e^-3` is a constant.

on the other hand if it is:
`int(5cos(10t)+12e^(-3t))dt=5sin(10t)/10+12e^(-3t)/-3+c=sin(10t)/2-4e^(-3t)+c`