Question

How do you integrate `int (2sinx+3cosx)dx`?

Answer 1

`3sinx-2cosx+C`

Explanation:

`int (2sinx+3cosx)dx= 2*int sinx dx + 3* int cosx dx`

Applying standard integrals:

`= 2*(-cosx) +3*sinx +C`

`=3sinx-2cosx+C`