How do you integrate $int pisinpix dx$ ?

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Answer 1 · 2016-12-06T21:13:13

Using $u$ -substitution, we will find a value in the function whose derivative will appear in the integrand.

Thus, we will let:

$u=pix$
$du=pidx$

So, if we plug it back in:

$=intsin(u)du$

$=-cos(u)+c$

$=-cos(pix)+c$

How do you integrate int pisinpix dxint pisinpix dx?