How do you integrate $\int ({sec}^{2} θ - sin θ) d θ$ $int (sec^2theta-sintheta)d theta$ ?

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Answer 1 · 2017-01-04T03:33:50

It is recommended that you know the following table of trig integrals by heart.

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Separating the integrals:

$= \int ({sec}^{2} θ) d θ - \int (sin θ) d θ$ $=int(sec^2theta)d theta - int(sin theta) d theta$

$= tan θ - (- cos θ) d$ $= tan theta - (-costheta) d$

$= tan θ + cos θ + C$ $= tan theta + costheta + C$

Hopefully this helps!

How do you integrate ∫(sec2θ−sinθ)dθint (sec^2theta-sintheta)d theta?