How do you integrate $\sqrt{3} sin x {(cos x)}^{0.5}$ $sqrt3sinx(cosx)^0.5$ ?

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How do you integrate $\sqrt{3} sin x {(cos x)}^{0.5}$ $sqrt3sinx(cosx)^0.5$ ?

1 Answer

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Answer 1 · 2016-05-04T08:54:09

$\int \sqrt{3} sin x {(cos x)}^{0.5} d x = - \frac{2 \sqrt{3}}{3} {(cos x)}^{1.5} + C$ $intsqrt3 sin x (cos x)^0.5 dx=-(2sqrt3)/3( cos x )^1.5+C$ .

Explanation:

The integral is $- \sqrt{3} \int {(cos x)}^{0.5} d (cos x)$ $-sqrt3int(cos x)^0.5d(cos x)$
$= - \sqrt{3} \frac{{(cos x)}^{0.5 + 1}}{0.5 + 1} + C$ $=-sqrt3( cos x )^(0.5+1)/(0.5+1)+C$
$= - \frac{2 \sqrt{3}}{3} {(cos x)}^{1.5} + C$ $= -(2sqrt3)/3( cos x )^1.5+C$

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How do you integrate $\sqrt{3} sin x {(cos x)}^{0.5}$ $sqrt3sinx(cosx)^0.5$ ?

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