How do you solve $0.25( 4f - 3) = 0.05( 10f - 9)$ ?

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Answer 1 · 2017-07-16T03:14:16

$f=0.6$

$0.25(\color(blue)(4f)\color(red)(-3))=0.05(\color(seagreen)(10f)\color(palevioletred)(-9))$

distributive
$\rArr0.25(\color(blue)(4f))+0.25(\color(red)(-3))=0.05(\color(seagreen)(10f))-0.05(\color(palevioletred)(-9))$
simplify
$\rArr\color(blue)(1)f\color(red)(-0.75)=\color(seagreen)(0.5f)\color(palevioletred)(-0.45)$
$\rArr\color(orange)(f)\color(skyblue)(-0.75)=\color(orange)(0.5f)\color(skyblue)(-0.45)$
combine like terms
$\rArr\color(orange)(f-0.5f)=\color(skyblue)(0.75-0.45)$
$\rArr\color(orange)(0.5f)=\color(skyblue)(0.30)$
get variable alone: $f=0.30\div0.5=0.6$
$\thereforef=0.6$

How do you solve 0.25( 4f - 3) = 0.05( 10f - 9)0.25( 4f - 3) = 0.05( 10f - 9)?