How do you solve $-0.25(4v-8)=0.5(4-2v)$ ?

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Answer 1 · 2018-05-23T02:48:58

As below.

$-0.25 (4v - 8) = 0.5 (4 - 2v)$

Using PEMDAS rule,

$-0.25 * 4v + 0.25 * 8 = 0.5*4 - 0.5*2v$ , removing bracelets.

$-v + 2 = 2 - v$ , multiplying.

$cancel(-v )+cancel (v )=cancel( 2) - cancel(2)$ , like terms together.

$0$

How do you solve -0.25(4v-8)=0.5(4-2v)-0.25(4v-8)=0.5(4-2v)?