How do you solve $0.40 x - 0.20 (50 + x) = - 0.04 (50)$ $0.40x - 0.20(50 + x) = -0.04(50)$ ?

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Answer 1 · 2016-03-06T15:29:08

$x = 40$ $color(blue)(x=40$

$0.40 x - 0.20 (50 + x) = - 0.04 (50)$ $0.40x−0.20(50+x)=−0.04(50)$

$0.40 x - 0.20 \times (50) + (- 0.20) \times (x) = - 0.04 (50)$ $0.40x−0.20 xx (50) + (−0.20) xx (x)=−0.04(50)$

$0.40 x - 10 - 0.20 x = - 2$ $0.40x -10 -0.20x= -2$

$0.40 x - 0.20 x = - 2 + 10$ $0.40x -0.20x= -2 +10$

$0.20 x = - 2 + 10$ $0.20x= -2 +10$

$0.20 x = 8$ $0.20x= 8$

$x = \frac{8}{0.20}$ $x=8/(0.20)$

$x = \frac{800}{20}$ $x=800/(20)$

$x = \frac{80}{2}$ $x=80/(2)$

$x = 40$ $color(blue)(x=40$

How do you solve 0.40x−0.20(50+x)=−0.04(50)0.40x - 0.20(50 + x) = -0.04(50)?