How do you solve $1/8(5y+64)=1/4(20+2y)$ ?

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Answer 1 · 2016-12-21T12:01:15

$y = -24$

$1/8(5y+64) = 1/4(2y+20)$

multiply both sides by 8:

$5y+64 = 2(2y+20)$

multiply out brackets:

$5y+64 = 4y+40$

subtract 4y from both sides:

$y+64=40$

subtract 64:

$y = 40-64 = -24$

$y=-24$

How do you solve 1/8(5y+64)=1/4(20+2y)1/8(5y+64)=1/4(20+2y)?