How do you solve $10 - 2 (n + 7) = 2 n + 16$ $10- 2( n + 7) = 2n + 16$ ?

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Answer 1 · 2017-09-27T07:05:25

$n = - 5$ $n = -5$

$10 - 2 (n + 7) = 2 n + 16$ $10 - 2(n + 7) = 2n + 16$

Removing the bracket first you will have..

$10 - 2 n - 14 = 2 n + 16$ $10 -2n -14 = 2n + 16$

Simplifying..

$- 2 n - 4 = 2 n + 16$ $-2n - 4 = 2n + 16$

Collecting like terms..

$- 2 n - 2 n = 16 + 4$ $-2n - 2n = 16 + 4$

$- 4 n = 20$ $-4n = 20$

$(cancel(-4n))/cancel4 = 20/4$

$-n = 20/4$

$-n = 5$

$n = -5$

How do you solve 10- 2( n + 7) = 2n + 1610−2(n+7)=2n+1610- 2( n + 7) = 2n + 16?