Question

How do you solve `12+5v=2v-9`?

Answer 1

See a solution process below:

Explanation:

First, subtract `color(red)(12)` and `color(blue)(2v)` from each side of the equation to isolate the `v` term while keeping the equation balanced:

`12 + 5v - color(red)(12) - color(blue)(2v) = 2v - 9 - color(red)(12) - color(blue)(2v)`

`12 - color(red)(12) + 5v - color(blue)(2v) = 2v - color(blue)(2v) - 9 - color(red)(12)`

`0 + (5 - color(blue)(2))v = 0 - 21`

`3v = -21`

Now, divide each side of the equation by `color(red)(3)` to solve for `y` while keeping the equation balanced:

`(3v)/color(red)(3) = -21/color(red)(3)`

`(color(red)(cancel(color(black)(3)))v)/cancel(color(red)(3)) = -7`

`v = -7`