How do you solve $13 - 4 x = 1 - x$ $13-4x=1-x$ ?

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How do you solve $13 - 4 x = 1 - x$ $13-4x=1-x$ ?

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Answer 1 · 2016-10-04T08:04:42

$x = 4$ $x = 4$

Explanation:

To solve an equation you need to have the variables on one side and the numbers on the other.
In order to keep the variable positive, move them to the right side.

$13 - 4 x = 1 - x \leftarrow$ $13-4x=1-x" "larr$ add +4x to both sides

$13 - 4 x + 4 x = 1 - x + 4 x$ $13-4xcolor(red)(+4x)=1-xcolor(red)(+4x)$

$13 - 1 = 1 + 3 x - 1 \leftarrow$ $13color(blue)(-1)= 1+3xcolor(blue)(-1)" "larr$ subtract 1 from each side

$12 = 3 x \leftarrow \div 3$ $12 = 3x" "larrdiv3$ to isolate x

$\frac{12}{3} = \frac{3 x}{3}$ $12/3 = (3x)/3$

$4 = x \leftarrow$ $4=x" "larr$ this is the solution

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How do you solve $13 - 4 x = 1 - x$ $13-4x=1-x$ ?

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How do you solve 13-4x=1-x13−4x=1−x13-4x=1-x?

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How do you solve $13 - 4 x = 1 - x$ $13-4x=1-x$ ?