How do you solve $15 (- 42 x + 40) = 15 (- 8 x + 244)$ $15(-42x+40) = 15(-8x+244)$ ?

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Answer 1 · 2018-04-21T15:11:47

$x = - 6$ $x=-6$

Divide both sides by 15

$\Rightarrow$ $=>$ - $42 x + 40 = - 8 x + 244$ $42x+40=-8x+244$

Add $42 x$ $42x$ to both sides

$40 = 34 x + 244$ $40=34x+244$

Subtract 244 from both sides

$- 204 = 34 x$ $-204=34x$

Divide both sides by 34

$- \frac{204}{34} = x$ $-204/34=x$

$x = - 6$ $x=-6$

How do you solve 15(-42x+40) = 15(-8x+244)15(−42x+40)=15(−8x+244)15(-42x+40) = 15(-8x+244)?