How do you solve $15+5(x-2)=7w+4$ ?

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Answer 1 · 2016-10-02T16:59:51

$x = (7w)/5 - 0.2$

Expand the brackets

$15 + 5x - 10 = 7w + 4$

$5x + 5 = 7w + 4$

Divide both sides by $5$

$x + 1 = (7w)/5 + 4/5$

$x + 1 = (7w)/5 + 0.8$

Take $5$ from both sides

$x = (7w)/5 - 0.2$

How do you solve 15+5(x-2)=7w+415+5(x-2)=7w+4?