How do you solve $18-2(3m-1)=(6+2(m+3))/2$ ?

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Answer 1 · 2017-06-30T01:23:55

$m=2$

Start by simplifying both left and right sides:

$18-2(3m-1)=(6+2(m+3))/2$

$18-6m+2=(6+2m+6)/2$

$20-6m=(12+2m)/2$

$20-6m=6+m$

Bring the variable to one side by subtracting $m$ to both sides while also subtracting $20$ to both sides to isolate the variable.

$cancel(20-20)-6m-m=6+cancel(m-m)-20$

$-7m=-14$

Solve for $m$ by dividing $-7$ from both sides:

$cancel(-7)/cancel(-7)m=(-14)/-7$

$m=2$

How do you solve 18-2(3m-1)=(6+2(m+3))/218-2(3m-1)=(6+2(m+3))/2?