Question

How do you solve `2 + 11b = 8b + 15`?

Answer 1

`b=13/3`

Explanation:

Collect terms in x on the left side of the equation and numeric values on the right side.

`"subtract 8b from both sides"`

`2+11b-8b=cancel(8b)cancel(-8b)+15`

`rArr2+3b=15`

`"subtract 2 from both sides"`

`cancel(2)cancel(-2)+3b=15-2`

`rArr3b=13`

`"divide both sides by 3"`

`(cancel(3) b)/cancel(3)=13/3`

`rArrb=13/3`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`"left side "=2+(11xx13/3)=6/3+143/3=149/3`

`"right side "=(8xx13/3)+15=104/3+45/3=149/3`

`rArrb=13/3" is the solution"`