How do you solve $(2+t)/3=4-6/7t$ ?

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Answer 1 · 2017-05-22T10:30:03

Soluttion : $t= 2 4/5$

$(2+t)/3 = 4 - 6/7t$ . LCM of denominators $3 and 7$ is $21$

Multiplying by $21$ on both sides we get,

$7(2+t) = 84 - 18t or 14 +7t =84 -18t or 7t+18t = 84-14 or 25t = 70$ or

$t= 70/25 = 14/5 = 2 4/5$

Soluttion : $t= 2 4/5$ [Ans]

How do you solve (2+t)/3=4-6/7t(2+t)/3=4-6/7t?