How do you solve $2(x+2)=3(x-8)$ ?

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Answer 1 · 2017-02-12T14:41:18

See the entire solution process below:

First, expand the terms in parenthesis on each side of the equation:

$(2 xx x) + (2 xx 2) = (3 xx x) - (3 xx 8)$

$2x + 4 = 3x - 24$

Now, subtract $color(red)(2x)$ and add $color(blue)(24)$ to each side of the equation to solve for $x$ :

$2x + 4 - color(red)(2x) + color(blue)(24) = 3x - 24 - color(red)(2x) + color(blue)(24)$

$2x - color(red)(2x) + 4 + color(blue)(24) = 3x - color(red)(2x) - 24 + color(blue)(24)$

$0 + 28 = (3 - 2)x - 0$

$28 = 1x$

$28 = x$

$x = 28$

How do you solve 2(x+2)=3(x-8)2(x+2)=3(x-8)?