How do you solve $2s-4.2=-8s+8$ ?

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Answer 1 · 2017-04-28T03:44:17

See the entire solution process below:

First, add $color(red)(4.2)$ and $color(blue)(8s)$ to each side of the equation to isolate the $s$ term while keeping the equation balanced:

$color(blue)(8s) + 2s - 4.2 + color(red)(4.2) = color(blue)(8s) - 8s + 8 + color(red)(4.2)$

$(color(blue)(8) + 2)s - 0 = 0 + 12.2$

$10s = 12.2$

Now, divide each side of the equation by $color(red)(10)$ to solve for $s$ while keeping the equation balanced:

$(10s)/color(red)(10) = 12.2/color(red)(10)$

$(color(red)(cancel(color(black)(10)))s)/cancel(color(red)(10)) = 1.22$

$s = 1.22$

How do you solve 2s-4.2=-8s+82s-4.2=-8s+8?