How do you solve $2 y - 10 + 18 y = 10 y - 3 \times 30$ $2y-10+18y=10y-3\times 30$ ?

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Answer 1 · 2018-06-24T20:10:50

$y = - 8$ $y = -8$

$2 y - 10 + 18 y = 10 y - 3 \times 30$ $2y - 10 + 18y = 10y - 3 xx 30$

Firstly, we make the multiplication:

$2 y - 10 + 18 y = 10 y - 90$ $2y - 10 + 18y = 10y - 90$

Secondly, we collect and put all of the similar elements from the one side and the numbers from the other side:

$2 y + 18 y - 10 y = 10 - 90$ $2y + 18y - 10y = 10 - 90$

$10 y = - 80$ $10y = -80$

$y = \frac{- 80}{10}$ $y = (-80)/10$

$y = - 8$ $y = -8$

Answer 2 · 2018-06-24T21:53:22

$y = - 8$ $y=-8$

We can start by combining our like terms to get

$20 y - 10 = 10 y - 90$ $20y-10=10y-90$

Next, we can add $10$ $10$ to both sides to get

$20 y = 10 y - 80$ $20y=10y-80$

Remember, we want our constants on one side, and our variables on the other. To do this, we can subtract $10 y$ $10y$ from both sides.

$10 y = - 80$ $10y=-80$

Lastly, dividing both sides by $10$ $10$ gives us

$y = - 8$ $y=-8$

Hope this helps!

How do you solve 2y-10+18y=10y-3\times 302y−10+18y=10y−3×302y-10+18y=10y-3\times 30?