How do you solve 32+34a=14a−12?

1 Answer
smendyka
Feb 10, 2017

See the entire solution process below:

Explanation:

First, subtract 32 and 14a from each side of the equation to isolate the a term while keeping the equation balanced:

32+34a−32−14a=14a−12−32−14a

32−32+34a−14a=14a−14a−12−32

0+(34−14)a=0−12−32

24a=−42

Now, multiply each side of the equation by 42 to solve for a while keeping the equation balanced:

42×24a=42×−42

88a=−164

1a=−4

a=−4

Related questions
See all questions in Equations with Variables on Both Sides
Impact of this question
2950 views around the world
You can reuse this answer
Creative Commons License