How do you solve $3(3m-2) = 2(3m+3)$ ?

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Answer 1 · 2016-11-04T11:26:25

$m = 4$

Step 1) Expand the terms in parenthesis
Step 2) Solve for $m$ while keeping the equation balanced

$9m - 6 = 6m + 6$

$9m - 6 + 6 = 6m + 6 + 6$

$9m - 0 = 6m + 12$

$9m = 6m + 12$

$9m - 6m = 6m - 6m + 12$

$3m = 0 + 12$

$3m = 12$

$(3m)/3 = 12/3$

$1m = 4$

$m = 4$

How do you solve 3(3m-2) = 2(3m+3)3(3m-2) = 2(3m+3)?