How do you solve $3 (4 x - 2) = - 2 (- 6 x + 3)$ $3(4x-2)=-2(-6x+3)$ ?

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Answer 1 · 2016-12-15T18:21:22

$x$ $x$ = any value

multiply out brackets:

$3 (4 x - 2) = 12 x - 6$ $3(4x-2)=12x-6$

$12 x - 6 = - 2 (- 6 x + 3)$ $12x-6=-2(-6x+3)$

$- 2 (- 6 x + 3) = 12 x - 6$ $-2(-6x+3)=12x-6$

$12 x - 6 = 12 x - 6$ $12x-6=12x-6$

Since both equations are the same, $x$ $x$ could have any value and still satisfy this system of equations.

How do you solve 3(4x-2)=-2(-6x+3)3(4x−2)=−2(−6x+3)3(4x-2)=-2(-6x+3)?