How do you solve -3(6x-4)=5x+28?

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Answer 1 · 2016-11-22T21:19:53

$x = (-16)/23$

Step 1) Expand the terms within parenthesis:

$-18x + 12 = 5x + 28$

Step 2) Add $18x$ to each side of the equation:

$-18x + 12 + 18x = 5x + 28 + 18x$

$12 = 23x + 28$

Step 3) Subtract 28 from each side of the equation:

$12 - 28 = 23x + 28 - 28$

$-16 = 23x$

Step 4) Divide each side of the equation by 23:

$(-16)/23 = (23x)/23$

$x = (-16)/23$