How do you solve $-3 [x + 5 - 2( 3x - 10) - (4x - 10] = -2 [3x - 7( x + 2)]$ ?

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Answer 1 · 2015-08-23T10:53:34

$color(blue)(x=7$

$−3[x+5−color(blue)(2(3x−10)−(4x−10)]]=−2[3x−color(blue)(7(x+2)]]$

$-3[x+5−6x+20 -4x +10]=−2[3x−7x-14]$

$−3[x+5−10x+30]=−2[−4x-14]$

$−3[-9x+35]=−2[−4x-14]$

$27x-105=8x +28$

$27x-8x=105 +28$

$19x=133$

$color(blue)(x=7$

How do you solve -3 [x + 5 - 2( 3x - 10) - (4x - 10] = -2 [3x - 7( x + 2)]-3 [x + 5 - 2( 3x - 10) - (4x - 10] = -2 [3x - 7( x + 2)]?